6=x-8-7/x+8=1/x^2-64

Solution for 6=x-8-7/x+8=1/x^2-64 equation:

6=x-8-7/x+8=1/x^2-64

We move all terms to the left:

6-(x-8-7/x+8)=0


Domain of the equation: x+8)!=0

x∈R


We add all the numbers together, and all the variables

-(+x-7/x)+6=0

We get rid of parentheses

-x+7/x+6=0

We multiply all the terms by the denominator


-x*x+6*x+7=0

We add all the numbers together, and all the variables

6x-x*x+7=0

Wy multiply elements

-1x^2+6x+7=0

a = -1; b = 6; c = +7;
Δ = b2-4ac
Δ = 62-4·(-1)·7
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*-1}=\frac{-14}{-2}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*-1}=\frac{2}{-2}
=-1
$